General Standing waves question
If a source of sound is placed at an open end of a pipe and travels to a closed end.(Closed end) is the lentgh (L=(n/2)*wavelentgh or (L=n/4)*Wavelentgh
Well with the first harmonic, we agree that 2L=lamda. Then for the second it's L=Lamda and then the third one, there are 1.5 wavelengths over the length of string (or here tube). So that means lamda = 2/3 L
so it's the denominator that is changing and we know this "2" is a constant, so 2L/n=lamda. Rearranging to find the constant of L, we get Lamda* n/2 = L
so it's the denominator that is changing and we know this "2" is a constant, so 2L/n=lamda. Rearranging to find the constant of L, we get Lamda* n/2 = L
Original post by DrSebWilkes
Well with the first harmonic, we agree that 2L=lamda. Then for the second it's L=Lamda and then the third one, there are 1.5 wavelengths over the length of string (or here tube). So that means lamda = 2/3 L
so it's the denominator that is changing and we know this "2" is a constant, so 2L/n=lamda. Rearranging to find the constant of L, we get Lamda* n/2 = L
so it's the denominator that is changing and we know this "2" is a constant, so 2L/n=lamda. Rearranging to find the constant of L, we get Lamda* n/2 = L
Thank you.
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