Algebraic equation solving

X-2 divided by 7 = 2 + (3-x) divided by 14.... Only 3-x is divided by 14
When working it out I got x=5 and the. another time I got x=9. But when substituting into x it doesn't statisfy the solution... Where have I gone wrong?
Many thanks for your help :smile:

Reply 1

Dalek1099

21

Original post by Musicanor

X-2 divided by 7 = 2 + (3-x) divided by 14.... Only 3-x is divided by 14
When working it out I got x=5 and the. another time I got x=9. But when substituting into x it doesn't statisfy the solution... Where have I gone wrong?
Many thanks for your help :smile:

Show some working so I can see at what line you made a mistake.

Reply 2

ArcaneMists

15

Are you cross multiplying?

Reply 3

Musicanor

OP

9

Original post by Dalek1099

Show some working so I can see at what line you made a mistake.

2x-4/ 14= 2+ 3-x/14
2+ 3-x-2x-4/14=0 also did with -2x+4
2-1-3x=14
1-3x=14
3x=15
X=5

(edited 6 years ago)

Reply 4

Musicanor

OP

9

Original post by ArcaneMists

Are you cross multiplying?

No but should I

Reply 5

Dalek1099

21

Original post by Musicanor

2x-4/ 14= 2+ 3-x/14
2+ 3-x-2x-4/14=0 also did with -2x+4
2-1-3x=14
1-3x=14
3x=15
X=5

Use brackets! I think you are confusing yourself by not using them. So start with (2x-4)/14=2+(3-x)/14. Then, its should be +4/14 on the second line you are subtracting minus 4/14 so a minus of a minus makes a plus. Next, when multiplying by 14 remember to also multiply 2 by 14 as well and 0 multiplied by anything is 0 so there should be no 14 on the right hand side.

Reply 6

Musicanor

OP

9

Original post by Dalek1099

Use brackets! I think you are confusing yourself by not using them. So start with (2x-4)/14=2+(3-x)/14. Then, its should be +4/14 on the second line you are subtracting minus 4/14 so a minus of a minus makes a plus. Next, when multiplying by 14 remember to also multiply 2 by 14 as well and 0 multiplied by anything is 0 so there should be no 14 on the right hand side.