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largest number watch

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    you have 10 charachters to give the largest number you can, use any symbols that will work on the forum.
    the one with the largest number, that proves that it is the largest, wins rep from everyone else that participates

    by giving a number you are agreeing to give this prize
    and no copying!
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    mine:

    9!!!!!!!!

    btw brackets DO NOT COUNT as they are not operations strictly
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    (Original post by Invisible)
    e^99999999

    Reason - Given the graph of y = e^x, once can observe that y increases exponentially with respect to x, so when x = 999999, y is +ve Infinity.
    Hence, e^999999 gives +ve Infinity.
    wait wait, y will just be very large, not infinity
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    (Original post by Invisible)
    e^99999999

    Reason - Given the graph of y = e^x, once can observe that y increases exponentially with respect to x, so when x = 999999, y is +ve Infinity.
    Hence, e^999999 gives +ve Infinity.
    Are you sure? e^99999999 is still a finite number, surely?
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    9^99999999 > e^99999999
    and neither are infinite .
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    What's 'e'?
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    (Original post by mobb_theprequel)
    What's 'e'?
    the number such that d(e^x)/dx = e^x
    I think
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    (Original post by mobb_theprequel)
    What's 'e'?
    A function that needs to have a number applied to it as an index in order to give an output value. As the index, i.e.) x, increases, the output value, i.e.) y, increases exponentially i.e.) It rapidly accelerates and increases to very large values.
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    (Original post by Invisible)
    Ok, scrap that, this is my submission as largest number:

    1/0
    Thats undefined.

    Mine is "googolplex". lol, its quite hard trying to work out what is largest.
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    googolplex, that's 10 charachters! sorry!

    I think that is (10^100)^(10^100), or a googol squared where a googol has 100 zeroes on the end of it.
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    (Original post by mik1a)
    googolplex, that's 10 charachters! sorry!

    I think that is (10^100)^(10^100), or a googol squared where a googol has 100 zeroes on the end of it.
    We have 10 characters...googolplex is 10 characters long. If i cant have that then i want 9^9^googol.
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    (Original post by JamesF)
    We have 10 characters...googolplex is 10 characters long. If i cant have that then i want 9^9^googol.
    Scrap googolplex, i want 9^9^googol anyway...its bigger
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    lol I thought it was 9, even though i wrote it.. :confused:

    unfortunately I can't allow googol or googolplex as a mathematical symbol as you wouldn't see it in an equation
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    Boooo... :mad:

    9^9^9^9^99
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    (Original post by Invisible)
    How do we know? What is the value of "9^99999999" then?
    6 > e
    9 > e + 3
    9^99999999 > (e + 3)^99999999

    3 > 0
    3 + e > e

    Thus 9^99999999 > (3 + e)^99999999 > e^99999999

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    Here is infinity itself hehe!


    ∞∞∞∞∞∞∞∞∞∞ hehee sorry looks nice though
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    this is going to be quite difficult to judge me thinks!

    $ x^x dx 0 9^9

    as in "integral of x^x between 0 and 9^9"

    hope that's allowed

    I guess a numerical approximation would be

    1^1 + 2^2 + 3^3 + 4^4 + ... + (9^9 - 1)^(9^9 - 1) + (9^9)^(9^9)
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    (Original post by Invisible)
    How do we know? What is the value of "9^99999999" then?
    As Mik1a has already shown e = 2.718281828....... whereas 9 is 9 .

    9 > 2.718281828....

    so if you multiply 9 by itself 99999999 times you get a number bigger than if you multiply e by itself 99999999 times.
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    (Original post by fishpaste)
    this is going to be quite difficult to judge me thinks!

    $ x^x dx 0 9^9

    as in "integral of x^x between 0 and 9^9"

    hope that's allowed

    I guess a numerical approximation would be

    1^1 + 2^2 + 3^3 + 4^4 + ... + (9^9 - 1)^(9^9 - 1) + (9^9)^(9^9)
    It is obvious though that (9^9^9)^(9^9) is bigger than the above sum.
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    (Original post by AntiMagicMan)
    It is obvious though that (9^9^9)^(9^9) is bigger than the above sum.
    Believable, but not obvious to me.
 
 
 
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