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Quick Maths question

Solve 1 = 1 - 2 cos t , for -3/2pi <= t <= 3/2pi

I'm getting pi/2 and 3/2pi as both values but it says that its pi/2 and -pi/2?

Thanks
cos t = 0
t= -3pi/2, -pi/2, pi/2, 3pi/2 since t inbetween 3pi/2 and -3pi/2,
t= -pi/2, pi/2

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