# Stuck on a factorisation question!

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#1
Hello! I apologise if this is basic, but I seem to have forgotten how to solve this ghastly question.

Factorise this fully:

2a^2 + 8ab - 4ac
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4 years ago
#2
What factors does each term have in common? What do they not have in common? Take out the factors that are shared between all three terms and see what you have left.
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#3
(Original post by ecila21)
What factors does each term have in common? What do they not have in common? Take out the factors that are shared between all three terms and see what you have left.
I'm still confused
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4 years ago
#4
(Original post by WillPhillips)
I'm still confused
Okay, what have you tried so far?

If I said to factorise 3x+6, what would you do? What about if I said to factorise 2a+3a?
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#5
(Original post by ecila21)
Okay, what have you tried so far?

If I said to factorise 3x+6, what would you do? What about if I said to factorise 2a+3a?
1) 3(x+2)
2) a(2+3) ?
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4 years ago
#6
(Original post by WillPhillips)
1) 3(x+2)
2) a(2+3) ?
Yes exactly (just realised that the second question wasn't a great question but oh well...). So to do that, you found what was in both of the terms (so x for the first question) and took it out. It's the same idea when you have those three terms. What do 2a^2, 8ab and -4ac have in common?

Sorry if I don't make much sense
1
#7
(Original post by ecila21)
Yes exactly (just realised that the second question wasn't a great question but oh well...). So to do that, you found what was in both of the terms (so x for the first question) and took it out. It's the same idea when you have those three terms. What do 2a^2, 8ab and -4ac have in common?

Sorry if I don't make much sense
They have a and are multiples of 2?
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#8
So confused
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4 years ago
#9
They are all multiples of 2a, correct, so maybe write it as 2a(...) ?

(Original post by WillPhillips)
They have a and are multiples of 2?
(Original post by WillPhillips)
So confused
1
#10
(Original post by GrabDrop)
They are all multiples of 2a, correct, so maybe write it as 2a(...) ?
No no, I think I had it. Is it 2a(a+4b-2c)?
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4 years ago
#11
(Original post by WillPhillips)
No no, I think I had it. Is it 2a(a+4b-2c)?
yeah
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#12
(Original post by GrabDrop)
yeah
Ah, huzzah!
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4 years ago
#13
Do you want in factorised by completing the square or by 2 brackets? I tried the 2 brackets thing now and I can tell u you wont get the nice 2 brackets answer. I got 2a(a + b - 2c)
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