A LEVEL Gravitational Field StrengthWatch
The question is:
‘The earth has a mass of 6x10^24kg. Show that the gravitational field strength of the earth is equal and opposite to the gravitational field strength of the sun at the distance of 260000k from the centre of the earth’
Me = 6*10^24 kg, Ms = 2*10^30 kg, Sep Dist = 1.5*10^11 m. Show |g_e| = |g_s| at 2.6 x 10^8 m from earth.
Me/Xe^2 = Ms/Xs^2 => Xs/Xe = √(Ms/Me) = 577
=> Xe : Xs ~ 1 : 577 => Xe = (1.5*10^11)/578
=> Xe = 2.6*10^8 m (2 s.f)
g = (6.67 * 10-11) x (5.97*10^24) / (radius of earth)^2 = 9.84 ~ 9.8 N / Kg
You can find the gravitational field strength of earth using this equation.
Are you sure the question you wrote down is correct, I assume the distance is in km?