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integrating by substitution C3 HELP

right so this one question has been ending me and idk wat is going on:



so getting dx in terms of du so we can make the substitution im left with:

to get it in terms of u we can sub u-4 into the e^2x because:

if you sub this back in and simplify i end up with


I honestly don't know what to do next. any help would be appreaciated!!

the answer is:
Reply 1
Original post by perspirationting
right so this one question has been ending me and idk wat is going on:



so getting dx in terms of du so we can make the substitution im left with:

to get it in terms of u we can sub u-4 into the e^2x because:

if you sub this back in and simplify i end up with


I honestly don't know what to do next. any help would be appreaciated!!

the answer is:


Factorise and use partial fractions.
Original post by 1 8 13 20 42
Factorise and use partial fractions.


what on earth is that
Original post by perspirationting
right so this one question has been ending me and idk wat is going on:



so getting dx in terms of du so we can make the substitution im left with:

to get it in terms of u we can sub u-4 into the e^2x because:

if you sub this back in and simplify i end up with


I honestly don't know what to do next. any help would be appreaciated!!

the answer is:


You're on the right track. Try partial fractions.
1u24u1u(u4)Au+Bu4\displaystyle \frac 1 {u^2-4u} \equiv \frac 1 {u(u-4)} \equiv \frac A u + \frac B {u-4}
Where A,BA, B are constants to be determined.
Reply 4
Partial fractions are not covered in AQA C3, so if you're not familiar just have a quick look online or whatever. Really not difficult stuff tho
Original post by 1 8 13 20 42
Factorise and use partial fractions.


Original post by _gcx
You're on the right track. Try partial fractions.
1u24u1u(u4)Au+Bu4\displaystyle \frac 1 {u^2-4u} \equiv \frac 1 {u(u-4)} \equiv \frac A u + \frac B {u-4}
Where A,BA, B are constants to be determined.


Hmm i've never been taught this/seen it in the textbook. i'll look up on partial fractions and try again. thanks!!

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