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    Please can someone help me factorise this expression.

    3(2x-1)^3(x-1)^2+6(2x-1)^2(x+1)^3
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    (Original post by sammychu00)
    Please can someone help me factorise this expression.

    3(2x-1)^3(x-1)^2+6(2x-1)^2(x+1)^3
    Just expand the whole lot, making very sure not to forget any terms. Use the binomial expansion as a shortcut for the (ax+b)^3 bits. You should end up with a huge quintic. I can't guarantee that what's left will factorise - if you're going to look for factors, have a look at trying to divide (either use inspection or algebraic long-division) a few factors - start with (x+1), (x+2), (x-1) etc. Use the coefficients of the x^5 and constant terms as clues as to what to try.
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    This expression does not factorise nicely, you must have made a mistake typing it.
 
 
 
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