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    (Original post by Qer)
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    Which part? What have you tried? What's confusing you?
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    Part a
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    (Original post by RDKGames)
    Which part? What have you tried? What's confusing you?
    Part a .I am struggling with this question from last 30 mins
    I don't know show to show that to x+y=sqroot 3 cos


    I used cos2 + sin2 =1
    But equally that I got there is not cos
    As I made sin and cos as a subject and the sub .....
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    Remember that you can use addition formula for  cos(4t+\pi /6) so you can expand it out in terms of sin(4t) and cos(4t).
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    (Original post by Qer)
    Part a .I am struggling with this question from last 30 mins
    I don't know show to show that to x+y=sqroot 3 cos


    I used cos2 + sin2 =1
    But equally that I got there is not cos
    As I made sin and cos as a subject and the sub .....
    Just checked it and x+y \neq \sqrt{3} \cos(t) so the question is invalid. Simple counter-example: t=0 and the two do not match.
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    Looks as though part (a) should be asking you to show that x + y = 2sqrt(3)cos(t).

    Suggest you have a go at that, using the identity for cos (a + b).
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    (Original post by Qer)
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    Confirming what others have said, this question has been incorrectly copied from an exam paper.

    See the real question here (Question 5).
 
 
 
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