Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    4
    ReputationRep:
    A trolley is being pulled at a constant force with an acceleration of 0.60m/s^2
    A mass of 0.5kg is then mixed to the trolley and nows accelerates at 0.48m/s^2
    What is the mass of the trolley?
    Offline

    15
    ReputationRep:
    If the force stays the same then you have
    Original ma=new ma
    Call x the mass of the trolley (or the original mass)

    Can you create an equation from this (remember the new mass is the trolley plus 0.5kg)
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    4
    ReputationRep:
    (Original post by Pastelx)
    If the force stays the same then you have
    Original ma=new ma
    Call x the mass of the trolley (or the original mass)

    Can you create an equation from this (remember the new mass is the trolley plus 0.5kg)
    I get up to F = M x 0.60ms^-2 = F = (M+0.5)0.48ms^-2
    Offline

    15
    ReputationRep:
    Okay if you expand that bracket and make the equations equal each other, you should be able to take the M out of the equation and get a suitable answer!
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    4
    ReputationRep:
    (Original post by Pastelx)
    Okay if you expand that bracket and make the equations equal each other, you should be able to take the M out of the equation and get a suitable answer!
    M x 0.60 = (0.48M + 0.5) x 0.48
    = 0.60M = 0.48M + 0.24
    = 0.60M - 0.48M = 0.24
    = 0.12M = 0.24
    = 0.24/0.12
    = 2kg
    • Thread Starter
    Offline

    4
    ReputationRep:
    Seams to work.
    Test 1 = 0.60ms^-2
    F= 2 x 0.60 = 1.20N
    Test 2 = 0.48ms^-2
    F= (2+0.5)0.48 = 1.20N
    Offline

    15
    ReputationRep:
    (Original post by Lokum)
    M x 0.60 = (0.48M + 0.5) x 0.48
    = 0.60M = 0.48M + 0.24
    = 0.60M - 0.48M = 0.24
    = 0.12M = 0.24
    = 0.24/0.12
    = 2kg
    Wonderful–there’s your answer!
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    4
    ReputationRep:
    Isn't there an easier method to get the answer?
    Offline

    15
    ReputationRep:
    (Original post by Lokum)
    Isn't there an easier method to get the answer?
    Nope just do simultaneous equations for m*a I believe

    Personally I’d do less lines of working but that’s the easiest method to work it out as far as I can tell
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    4
    ReputationRep:
    Just made up a formula!

    a2 x added mass / change in a

    e.g 048 x 0.5 / 0.12 = 2kg

    Trolley 1
    A = 0.70m/s^2
    Trolley 2
    A = 0.50m/s^2
    M2 = M1 + 1.5

    M1 = 0.50 x 1.5 / (0.70-0.50) = 3.75 Kg
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    What newspaper do you read/prefer?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.