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# Simplifying watch

1. I have this question.

Now, after a few days practice, and starting on negative and fractional indices yesterday, I believe I understand indices to the extent that I can implement the techniques required to solve this individually. What I am unsure about is the order I need to implement them in. Should I be expanding the brackets first i.e and then , then or should I be doing this later, and doing other things first? Or is the order irrelevant? It seems the order matters because I know what the solution to this question is, but I can't quite seem to reach it.
2. Brackets first, remember ur BODMAS (order of operations)
3. So I need to do everything inside the brackets before I expand them? E.g

If this is the case, would I then expand them and then multiply by the ?
4. one way you could do this would to do the brackets 4 times, as it's to the power of 4, you're not multiplying the brackets by 4

Spoiler:
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i think
5. (Original post by Illidan2)
So I need to do everything inside the brackets before I expand them? E.g

If this is the case, would I then expand them and then multiply by the ?
The cube root only 'acts' on x - not the 2 as well.
6. (Original post by minertommy)
one way you could do this would to do the brackets 4 times, as it's to the power of 4, you're not multiplying the brackets by 4

Spoiler:
Show

i think
I know, what I meant was to multiply the contents of the brackets by the power four, I.e the contents of the brackets by themselves four times, perhaps it was a poor choice of words on my part.
7. (Original post by Muttley79)
The cube root only 'acts' on x - not the 2 as well.
Oh I see, so 2 takes the place of 1, and x remains in the square root alone?
8. (Original post by Illidan2)
Oh I see, so 2 takes the place of 1, and x remains in the square root alone?
The 2 should be on the numerator.
9. So then I have and then . Where do I go from there? I'm not sure if what i've done is right, because I can't see how I get to the solution from this.

Edit: Unless ? In hindsight, I think it is this.

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