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# Stats Question HELP! watch

1. A biased die has faces numbered 1 to 6. The probabilities of the die landing on 1, 3 or 5 are each equal to 0.1. The probabilities of the die landing on 2 or 4 are each equal to 0.2. The die is thrown twice. Find the probability that the sum of the numbers it lands on is 9.
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P(6) = 0.3. You can have 3&6, 6&3, 4&5, 5&4. Find the prob of each scenario, then sum them.
3. (Original post by Physics Enemy)
P(6) = 0.3. You can have 3&6, 6&3, 4&5, 5&4. Find the prob of each scenario, then sum them.
Oh okay I can do that but how you got the prob of 6?
Also please have a look to this question as well.
https://www.thestudentroom.co.uk/sho...8#post74015098
I am still confused.
Thank you
How'd you get the prob of 6?
P (total) = 1; P(6) = 1 - 3(0.1) - 2(0.2) = 0.3
5. (Original post by Physics Enemy)
P (total) = 1; P(6) = 1 - 3(0.1) - 2(0.2) = 0.3
Thank you
Please have a look to that question if you have time to.

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