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# Continuity Correction? watch

1. When to use Continuity Correction in Normal Distribution?
I am confused. Please make it clear.
When to use Continuity Correction in Normal Distribution?
I am confused. Please make it clear.

You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

* In the continuous world, 5 means 5
* In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

3. (Original post by old_engineer)
You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

* In the continuous world, 5 means 5
* In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

Thats clear. Thank you
We can use it when mean and sd is not given only n and prob, so we have to find both and then use continuity correction for the given value. Is that right?
4. (Original post by old_engineer)
You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

* In the continuous world, 5 means 5
* In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

Also
https://www.thestudentroom.co.uk/sho...8#post74015098
Can you help me out on this question as I am really confused. Thank you
Thats clear. Thank you
We can use it when mean and sd is not given only n and prob, so we have to find both and then use continuity correction for the given value. Is that right?
Let's say we have a random variable X with Poisson distribution, and that we wish approximate X with a new random variable Y that has normal distribution. Consider what happens when we try to use the approximation to find the value of P(X = 5). We can't simply map P(X = 5) to P(Y = 5) because P(Y = 5) = 0. To get round this fundamental problem, we apply a continuity correction and map P(X = 5) to P(4.5<= Y < 5).

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