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    When to use Continuity Correction in Normal Distribution?
    I am confused. Please make it clear.
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    (Original post by kundanad)
    When to use Continuity Correction in Normal Distribution?
    I am confused. Please make it clear.

    You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

    * In the continuous world, 5 means 5
    * In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

    If struggling with this concept, please post an example question and your attempt at answering it.
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    (Original post by old_engineer)
    You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

    * In the continuous world, 5 means 5
    * In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

    If struggling with this concept, please post an example question and your attempt at answering it.
    Thats clear. Thank you
    We can use it when mean and sd is not given only n and prob, so we have to find both and then use continuity correction for the given value. Is that right?
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    (Original post by old_engineer)
    You apply continuity corrections when using a continuous distribution (typically the normal distribution) as an approximation for a discrete distribution (typically the binomial or Poisson distributions). The need for these corrections arises because:

    * In the continuous world, 5 means 5
    * In the discrete world 5 means anything in the interval 4.5 =< a < 5.5

    If struggling with this concept, please post an example question and your attempt at answering it.
    Also
    https://www.thestudentroom.co.uk/sho...8#post74015098
    Can you help me out on this question as I am really confused. Thank you
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    (Original post by kundanad)
    Thats clear. Thank you
    We can use it when mean and sd is not given only n and prob, so we have to find both and then use continuity correction for the given value. Is that right?
    Let's say we have a random variable X with Poisson distribution, and that we wish approximate X with a new random variable Y that has normal distribution. Consider what happens when we try to use the approximation to find the value of P(X = 5). We can't simply map P(X = 5) to P(Y = 5) because P(Y = 5) = 0. To get round this fundamental problem, we apply a continuity correction and map P(X = 5) to P(4.5<= Y < 5).
 
 
 
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