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# Area Of A Trapezium watch

1. Hello,

I'm stuck on the following question, and would appreciate any help.

"The area of a trapezium is 18x^2 y + 12y^3. If the lengths of the parallel sides are 6xy^-1 and 4x-1y cm, find the height of the trapezium. (3 marks)"

(The area is 18x to the power of 2 and then y, not 18x^2y).

This is what I have so far:
A= a+b/2 x h
h= 2 A/a+b
h= 2 x 18x^2y+ 12y^3/ 6xy^-1 + 4x^-1y
h= 36x^2y + 24y^3/ 12xy^-1 + 8x^-1y

Could anyone help with the next step?
Thanks
2. Sorry if the formatting is a little confusing~
3. (Original post by TeacupAndTragedy)
Hello,

I'm stuck on the following question, and would appreciate any help.

"The area of a trapezium is 18x^2 y + 12y^3. If the lengths of the parallel sides are 6xy^-1 and 4x-1y cm, find the height of the trapezium. (3 marks)"

(The area is 18x to the power of 2 and then y, not 18x^2y).

This is what I have so far:
A= a+b/2 x h
h= 2 A/a+b
h= 2 x 18x^2y+ 12y^3/ 6xy^-1 + 4x^-1y
h= 36x^2y + 24y^3/ 12xy^-1 + 8x^-1y

Could anyone help with the next step?
Thanks
Could you upload a photo of your working? I can't follow this.
4. (Original post by Muttley79)
Could you upload a photo of your working? I can't follow this.
Sorry.. I know it's a little messy.

What would be the best way to upload a photo?
5. (Original post by TeacupAndTragedy)
Sorry.. I know it's a little messy.

What would be the best way to upload a photo?
It's the powers that are confusing - I only answer question so I can't help on uploading. It must say somewhere ...

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