I have been asked to work out the hardness of water in German degrees and this is what I did:
I got a sample of water I didn’t measure how much I put into my volumetric flask perhaps it was 8.5ml but I don’t think I need it, but I do use it ,which made me believe I was wrong.
The sample was made up to 100ml
10ml of this dilution was used as the anaylte along with buffer and the indicator
I Titrated 9.07ml of EDTA with a concentration of 0.0185moldm3
So the calculation i did was
Moles of edta= (9.07x0.0185)/1000= 0.000167795
Moles of Ca2+ is the same
So then I find the mass of Ca = 40x0.000167795= 0.0067188g
Now my issue
So 0.0067188g of Ca in the 10ml therefore in the 100ml there will be 10 times that, as it was a dilution. So 0.067188g which is 67.118mg
So there is 67.118mg of Ca in my 8.5ml sample/ 100ml volumetric flask
Now a 1 German degree is 10mg of Ca per 1000ml So is there 7896.2mg in 1000ml of sample Therefore having 789.6 German degree of hardness?
I think this is wrong though
Claims damages because he didn't get a first