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# C3 Trig watch

1. Given that x= cosec(Y) + cot (Y) find value of Y that satisfy the equation x+1/x=4 giving your solutions in the interval 0<Y<360
2. Can you show what you've tried, and show where you got stuck?
3. I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
4. (Original post by Niamh99)
I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
I feel like you should arrange into another x= expression so you can do x=x, i also feel like you should rearrange such that it's only 1 trig function. that makes things easier right?
5. [QUOTE=will'o'wisp2;74039116]I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
6. (Original post by Niamh99)
I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
You can simplify quite nicely. Try writing it as a single fraction. Hint once you've got there, (use ). You should then be able to cancel a factor.
7. (Original post by Niamh99)
(Original post by will'o'wisp2)
I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
you missed the
lol nvm

but where does that come from tho?

cosec=1/sin and cot is 1/tan or cos/sin

ah i see ambiguous notiation lol so it's

in which case then i think you should complete the square on and rearrange for x= and you should probably still rearrange the trig stuff into a single trig function
8. [QUOTE=Niamh99;74039286]
(Original post by will'o'wisp2)
I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
(Original post by _gcx)
You can simplify quite nicely. Try writing it as a single fraction. Hint once you've got there, (use ). You should then be able to cancel a factor.
^^ this guy , use this
9. Thank you guys, I’ve solved it now

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