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    Given that x= cosec(Y) + cot (Y) find value of Y that satisfy the equation x+1/x=4 giving your solutions in the interval 0<Y<360
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    Can you show what you've tried, and show where you got stuck?
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    I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
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    (Original post by Niamh99)
    I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
    I feel like you should arrange \dfrac{x+1}{x} =4 into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
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    [QUOTE=will'o'wisp2;74039116]I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
    So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
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    (Original post by Niamh99)
    I tried to sub in cosec(Y) + Cot(Y) into x+1/x=4 but I wasn’t sure if this was the right method. Do you think this is the right method? Or is there something else I should do first?
    You can simplify \csc(y) + \cot(y) + \frac 1 {\csc(y)+\cot(y)} quite nicely. Try writing it as a single fraction. Hint once you've got there, \cot^2(y) + 1 = ? (use \sin^2(y)+\cos^2(y) \equiv 1). You should then be able to cancel a factor.
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    (Original post by Niamh99)
    (Original post by will'o'wisp2)
    I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
    So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
    you missed the
    lol nvm

    but where does that come from tho?

    cosec=1/sin and cot is 1/tan or cos/sin

    ah i see ambiguous notiation lol so it's x + \dfrac{1}{x} =4

    in which case then i think you should complete the square on x + \dfrac{1}{x} =4 and rearrange for x= and you should probably still rearrange the trig stuff into a single trig function
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    [QUOTE=Niamh99;74039286]
    (Original post by will'o'wisp2)
    I feel like you should arrange \dfrac{x+1}{x} =4. into another x= expression so you can do x=x, i also feel like you should rearrange cosec(y)+cot(y) such that it's only 1 trig function. that makes things easier right?
    So if I rearranged cosec(Y) + cot(Y) = x to [1+cos(Y)/sin(Y)] do you think i could put that into x+ (1/x) = 4 ?
    (Original post by _gcx)
    You can simplify \csc(y) + \cot(y) + \frac 1 {\csc(y)+\cot(y)} quite nicely. Try writing it as a single fraction. Hint once you've got there, \cot^2(y) + 1 = ? (use \sin^2(y)+\cos^2(y) \equiv 1). You should then be able to cancel a factor.
    ^^ this guy , use this
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    Thank you guys, I’ve solved it now
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