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    a soloution of sodium carbonate has a concentration of 0.0157 mold dm3. what volume of soloution contains exactly 1.00g of sodium carbonate. mr is given as 106
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    moles = mass / Mr
    moles = 1.00 / 106
    moles = 0.00943

    concentration = moles / volume
    volume = moles / concentration
    volume = 0.00943 / 0.0157
    volume = 0.601 dm3
 
 
 
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