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    Someone help me with this exam question 'Cobalt is reacted with hydrogen to form cobalt. Co304+……. H2>3Co+…… H2O

    I've been the answer, but I need help knowing how to balance the equation.
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    With the 3 colbalt already being balanced on both sides we know that there is only 1 Co3O4, this means that we balance whatever is linked with the colbalt next meaning there must be 4 oxygens on the right side, for that to be the case you times the H2O by 4 making it 4H2O, this means the only thing left to balance is the hydrogen, as there a 8 H's on the right side there must be 8 on the second leading to 4H2 on the left Side so the full balanced equation is:
    Co3O4 + 4H2 ----> 3Co + 4H2O

    (Original post by SBizzy)
    Someone help me with this exam question 'Cobalt is reacted with hydrogen to form cobalt. Co304+……. H2>3Co+…… H2O

    I've been the answer, but I need help knowing how to balance the equation.
 
 
 
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