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How would I calculate the number of electrons passing through the cathode? Watch

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    I also need to calculate the total number of silver atoms from it.

    I know the current (0.12 A) the time (1200s) The charge (144C) and Change in mass (0.14g)
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    Please do your homework yourself!
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    (Original post by Ukvoltaire)
    Please do your homework yourself!
    I don't know how to do it this is just one of the 5 I need to work out. I wanted to find out how to do one then the other 4 I'll do on my own. The other 4 have different charges, Amps and change in weight. Could you just give me a formulae to work it out we weren't taught this.
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    (Original post by Balkaran)
    I also need to calculate the total number of silver atoms from it.

    I know the current (0.12 A) the time (1200s) The charge (144C) and Change in mass (0.14g)
    The elementary electric charge carried by an individual electron is:

    e = 1.6022\text{x}10^{-19} \text{ Coulombs}

    Each Coulomb of charge therefore has:

    \frac{1}{e} = 6.2414\text{x}10^{18} \text{ electrons}
 
 
 
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