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    Hi, please can someone help me with the equation

    3^x-3^(2-x)=8

    I believe that you have to find the same base, then set the exponents equal. It is the first stage that I am struggling with.
    Thanks so much

    Edward
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    (Original post by Edwarddelve01)
    Hi, please can someone help me with the equation

    3^x-3^(2-x)=8

    I believe that you have to find the same base, then set the exponents equal. It is the first stage that I am struggling with.
    Thanks so much

    Edward
    3^(2-x) = 3^2 multiplied by 3^-x does that help?
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    (Original post by Edwarddelve01)
    Hi, please can someone help me with the equation

    3^x-3^(2-x)=8

    I believe that you have to find the same base, then set the exponents equal. It is the first stage that I am struggling with.
    Thanks so much

    Edward
    Well i know that x=2 just trying to work out a way of writing that to get the answer
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    (Original post by Muttley79)
    3^(2-x) = 3^2 multiplied by 3^-x does that help?
    Thanks for trying, but I’m looking for a way to make the 3 and 8 the same using exponents, can you help with that bit? Thanks again
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    (Original post by roborto1999)
    Well i know that x=2 just trying to work out a way of writing that to get the answer
    I had used wolfram alpha to find that solution, but without pro I can’t see the steps. Can you help me with that?
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    (Original post by Edwarddelve01)
    Thanks for trying, but I’m looking for a way to make the 3 and 8 the same using exponents, can you help with that bit? Thanks again
    Try multiplying through by 3^x - then I think you get a quadratic.

    I don't think it's what you think.
 
 
 
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