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# MAT Question with respect to Integration watch

1. -RM-
2. (Original post by UCASLord)
Given a function f(x), you are told that:

and

The mark scheme rearranges this to:

3A + 2B = 7 (which is fine)
(A + B) + B = 1 (the part I don't understand)

The part I don't understand is why the is rearranged as (A + B). Is there something that's missing in my understanding of integration?

0 to 2 is 0 to 1 and then 1 to 2
3. (Original post by UCASLord)
Given a function f(x), you are told that:

and

The mark scheme rearranges this to:

3A + 2B = 7 (which is fine)
(A + B) + B = 1 (the part I don't understand)

The part I don't understand is why the is rearranged as (A + B). Is there something that's missing in my understanding of integration?

A is the area under f between 0 and 1 and B is the area under f between 1 and 2. Adding these gives the area between 0 and 2.
4. -RM-
5. (Original post by UCASLord)
*Strong Facepalm*
A useful smillie:

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