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    "I have 7 yoghurts to last the week: 2 strawberry; 2 Peach;3 Raspberry. I select 1 yoghurt each day.
    a) In how many different orders can I eat the yoghurts?
    b) If I select a yoghurt at random each day, what is the probability that I eat the two strawberry ones on consecutive days?"

    I think for part a you do 7(permutation)7, which gives you 5040 . But I'm not sure if that correct or not.
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    a) 7!/(3!*2!*2!) = 210
    b) [6!/(3!*1!*2!)]/[7!/(3!*2!*2!)] = 60/210 =2/7
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    (Original post by DotCoder)
    a) 7!/(3!*2!*2!) = 210
    b) [6!/(3!*1!*2!)]/[7!/(3!*2!*2!)] = 60/210 =2/7
    Thank you, would you possibly be able to help me with the second question on this post ... https://www.thestudentroom.co.uk/sho....php?t=4990330
 
 
 

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