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    A solution of potassium hydroxide contains 5.60gdm^-3. This solution is used to neutralise 20.0 cm^3 of a solution of sulphuric acid of concentration 0.05moldm^-3.
    A)Write an equation for the reaction.
    B)Determine the volume of potassium hydroxide solution that is required to neutralise the sulphuric acid.
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    Hopefully you have worked out the balanced equation?
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    (Original post by TutorsChemistry)
    Hopefully you have worked out the balanced equation?
    yeh but second part
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    Step by step we have:

    What is the concentration of the potassium hydroxide in mol dm-3 ?
    How many moles of sulphuric acid are present in the 20cm3 ?
    How many moles of KOH are need to exactly neutralise the acid?
    What volume contains exactly that number of moles?
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    Thank you
 
 
 
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