complex compound

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Snowie9
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#1
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#1
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Size:  505.8 KBHi can someone please tell me how to get the answer on part d)ii)?
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alow
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#2
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#2
Why not just AgNCO?

Are you sure your answer is wrong?
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Snowie9
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#3
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(Original post by alow)
Why not just AgNCO?

Are you sure your answer is wrong?
I'm wondering why is that not the answer too. But the one i wrote is exactly the answer on the marking scheme
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alow
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(Original post by Snowie9)
I'm wondering why is that not the answer too. But the one i wrote is exactly the answer on the marking scheme
It's a suggest question so I bet you would get the marks for either, as both can be linear.
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ChemistryWebsite
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#5
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(Original post by alow)
Why not just AgNCO?

Are you sure your answer is wrong?
AgNCO is not a complex and not linear.
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alow
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(Original post by TutorsChemistry)
AgNCO is not a complex and not linear.
That's irrelevant. Unless the specific example was taught, there's no reason for an A Level student to not think AgNCO is a linear complex.
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ChemistryWebsite
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#7
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(Original post by alow)
That's irrelevant. Unless the specific example was taught, there's no reason for an A Level student to not think AgNCO is a linear complex.
Ar A level students should know that linear complexes have 2 ligands.
It is always relevant to answer the question and not just pick some words from the question, ignoring what isn't liked.
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Snowie9
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(Original post by TutorsChemistry)
Ar A level students should know that linear complexes have 2 ligands.
It is always relevant to answer the question and not just pick some words from the question, ignoring what isn't liked.
I see thanks! So for tetrahedral there's four?
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ChemistryWebsite
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(Original post by Snowie9)
I see thanks! So for tetrahedral there's four?
Yes. Also 4 in square planar.
6 in octohedral.

Usually when questioning about complex shapes the ligand will be monodentate, like your example ligand.
Just be aware to watch for polydentate ligands.
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Snowie9
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#10
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#10
(Original post by TutorsChemistry)
Yes. Also 4 in square planar.
6 in octohedral.

Usually when questioning about complex shapes the ligand will be monodentate, like your example ligand.
Just be aware to watch for polydentate ligands.
I see. How do you write the charge of the complex?
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ChemistryWebsite
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#11
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#11
Put a square bracket around the entire formula, and the charge after the closing bracket
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Snowie9
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#12
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#12
(Original post by TutorsChemistry)
Put a square bracket around the entire formula, and the charge after the closing bracket
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ChemistryWebsite
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#13
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#13
The table or the stability constant part?

Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
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Snowie9
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#14
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#14
(Original post by TutorsChemistry)
The table or the stability constant part?

Hint: Double check the coordination number of the iron complex. Is the ethanedioate ligand monodentate or bidentate?
The table. I see it now based on what you told me earlier but i do not understand complex D. I know the ligand is neutral and therefore the charge is +2 but why the ligand have to be 3?
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#15
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#15
(Original post by Snowie9)
The table. I see it now based on what you told me earlier but i do not understand complex D. I know the ligand is neutral and therefore the charge is +2 but why the ligand have to be 3?
For D the ligand isn't neutral. It has a 2- charge per ion.
This ligand is bidentate, so forms 2 coordinate bonds per ligand to the iron ion. The coordination number for iron in this complex is 6 (3 ligands providing 2 coordinate bonds each).

The ligand is the ion of the dicarboxylic acid ethandioic acid (also called oxalic acid).
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Snowie9
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#16
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#16
(Original post by TutorsChemistry)
For D the ligand isn't neutral. It has a 2- charge per ion.
This ligand is bidentate, so forms 2 coordinate bonds per ligand to the iron ion. The coordination number for iron in this complex is 6 (3 ligands providing 2 coordinate bonds each).

The ligand is the ion of the dicarboxylic acid ethandioic acid (also called oxalic acid).
Are you talking about complex D? D has Nickel
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ChemistryWebsite
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#17
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#17
Sorry, my mistake.

The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
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ChemistryGuy1998
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#18
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#18
For D: Coordination number is 6 - 6 lone pairs, therefore it is an octahedral complex.

H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
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Snowie9
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#19
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#19
(Original post by TutorsChemistry)
Sorry, my mistake.

The ligand in D is also bidentate, eacg ligand molecule makes 2 coordinate bonds with the nickel ion. The bond is from the lone pair on each nitrogen atom.
As there are 2 coordinate bonds per ligand, only 3 ligand molecules are required to satisfy the coordination number of 6.
I see! Thanks!!
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Snowie9
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#20
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#20
(Original post by ChemistryGuy1998)
For D: Coordination number is 6 - 6 lone pairs, therefore it is an octahedral complex.

H2NCH2CH2NH2 is a bidentate ligand, therefore you need 3 of these to fulfill the coordination number 6 as the N atom has 2 lone pairs on each (2x3=6)
Thank you! I got it now
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