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    im not sure how to approach (a) since the angles are different? Any help is appreciated
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    Haha. That's a good exam question.
    There's a lesser known identity relating sin and cos (not the squared one). It's cos(x) = sin(A-x)
    See if you can figure out what A is from looking at the graphs.
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    https://www.desmos.com/calculator/o9k8zoifma

    This might help. What value of A maps the moving graph onto the sin curve?

    Edit:

    Sorry do this one.
    That's in radians
    https://www.desmos.com/calculator/52pdkfadkg
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    A hint below:

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    Write out what:  \sin(90^{\circ} - x^{\circ}) is and use this identity.



 
 
 
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Updated: October 10, 2017
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