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    Sanket plays a game using a biased die which is twice as likely to land on an even number as on an odd number. The probabilities for the three even numbers are all equal and the probabilities for the three odd numbers are all equal.
    (i) Find the probability of throwing an odd number with this die.
    Sanket throws the die once and calculates his score by the following method.
    • If the number thrown is 3 or less he multiplies the number thrown by 3 and adds 1.
    • If the number thrown is more than 3 he multiplies the number thrown by 2 and subtracts 4.
    The random variable X is Sanket’s score.
    (ii) Show that P(X = 8) = 2 9.
    Please help me out on solving as my exams are near.
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    Prob(even) is twice prob(odd) and the probs must add up to 1. So now you know prob(odd). Then each even number has equal probability and same for the odds.
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    (Original post by Matureb)
    Prob(even) is twice prob(odd) and the probs must add up to 1. So now you know prob(odd). Then each even number has equal probability and same for the odds.
    Oh okay Thank you
    Could you also help me out on those question that I tagged you in.
 
 
 
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Updated: October 10, 2017
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