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    e^2x +1/e^x

    i have tried to work it out but I'm not sure if its right. the answer I got was...

    2e^2x/ e^x

    Thanks in advance
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    im not 100% sure but i got

    2e^2x - e^-x
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    (Original post by Butterflyshy)
    e^2x +1/e^x

    i have tried to work it out but I'm not sure if its right. the answer I got was...

    2e^2x/ e^x

    Thanks in advance
    Looks, like you've just differentiated the top and bottom separately, and stuck them back together. Not correct, I'm afraid. You could use product rule, or quotient rule on it, but the easiest method is:


    Performing the division first of all to sort out the fraction, and then differentiate.

    From looking at your answer, I am infering that the original function is (e^2x +1)/e^x.
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    (Original post by Butterflyshy)
    e^2x +1/e^x

    i have tried to work it out but I'm not sure if its right. the answer I got was...

    2e^2x/ e^x

    Thanks in advance
    (e^2x +1)/e^x or e^2x + 1/e^x ?

    It's incorrect, how did you get this answer?
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    Do you know how to differentiate "e^(ax)" (where a is a constant)?

    Also is the expression to differentiate:

    * \quad e^{2x} + \dfrac{1}{e^{x}},

    or:

    * \quad \dfrac{e^{2x} + 1}{e^{x}}?
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    (Original post by simon0)
    Do you know how to differentiate "e^(ax)" (where a is a constant)?

    Also is the expression to differentiate:

    * \quad e^{2x} + \dfrac{1}{e^{x}},

    or:

    * \quad \dfrac{e^{2x} + 1}{e^{x}}?
    It's the second one except its not 2e^2x but e^2x
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    2 e^ 2 x − e ^ -x that’s what I got
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    I am now getting the answer as e^x-e^-x
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    (Original post by KillerCosine)
    2 e^ 2 x − e ^ -x that’s what I got
    can you explain how you got that answer pls
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    (Original post by Butterflyshy)
    It's the second one except its not 2e^2x but e^2x
    Okay, we can go two ways:

    * We can divide through the numerator (top part) by "e^x", then we can differentiate.

    * Use the differentiation rule where we divide a fraction expression (the rule starts with a "q").

    Can you take either of these further?
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    (Original post by KillerCosine)
    2 e^ 2 x − e ^ -x that’s what I got
    Not this as we now know the expression to differentiate.
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    (Original post by Butterflyshy)
    I am now getting the answer as e^x-e^-x
    Yes, this is the answer. :-)
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    (Original post by Butterflyshy)
    I am now getting the answer as e^x-e^-x
    If your original function was (e^2x+1)/e^x, then that answer is correct.
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    (Original post by simon0)
    Yes, this is the answer. :-)
    Thanks
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    (Original post by simon0)
    Not this as we now know the expression to differentiate.
    Oh thanks just realised . Thanks
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    wait was your question (e^2x) + (1/e^x) OR (e^2x+1)/e^x
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Size:  501.5 KB Btw there's a little squiggle
 
 
 
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