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    Please help me solve it!
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    (Original post by funkybinoculars)
    Please help me solve it!
    What have you tried?

    I have some helpful hints waiting for you..

    Look here: https://www.thestudentroom.co.uk/sho....php?t=4919248

    for some advice on asking questions here.
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    don't know how to solve it, but i think if you solve

    x^3-7x^2+4x=0

    then you'll get the answer
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    (Original post by SmartJay)
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    (Original post by lulal)
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    (Original post by Hey_Its_Cerian)
    x
    Full solutions are against the rules of the maths forum so they have been removed. Please read the posting guidelines, thanks
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    This is an equation with 3 solutions as one of the terms is x^3.
    I suggest moving all terms to one side and then factorising. It is a relatively simple factorisation.

    (Original post by funkybinoculars)
    Please help me solve it!
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    (Original post by 10preciousola)
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    As Notnek has commented above, posting full solutions is against forum rules. Please remove them from your comment.
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    (Original post by funkybinoculars)
    Please help me solve it!
    Factorise the LHS, bring everything to one side and then factorise again.

    A little tip: if you have a common variable or expression on both sides of an equation, do not cancel it, instead, set it equal to zero and solve it as one of your solutions. For example,

     x^2+5x = bx

     x(x+5)= bx

     x = 0 \text{ or } x+5=b

    If we had cancelled the x we would've missed a solution. This is a very common mistake that people make, even at the end of their A levels!
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    (Original post by Notnek)
    Full solutions are against the rules of the maths forum so they have been removed. Please read the posting guidelines, thanks
    Sorry, my mistake. Never posted in the Maths forum so I didn't realise.
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    You have  x(x-2)=x(x-2)(x-3) so two solutions can be seen straight away, namely x=0 and x=2 because they're common to both sides.
    If you account for a solution then you can cancel the factors on both sides essentially so you already have two solutions so the equation just becomes  1=x-3 which is easy to solve.
 
 
 
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