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# Chemistry (Calculating mass of reactant or product using formula masses - higher) watch

1. What mass of carbon dioxide is formed when 7.41 g of copper (II) carbonate decomposes on heating?
2. The number of moles of CO2 formed is the same as the number of moles of CuCO3, because when one molecule of CuCO3 decomposes it produces one molecule of CO2. So start by working out the number of moles of CuCO3 in 7.41g.
Atomic mass values:
Cu = 63.5 g/mol
C = 12 g/mol
O = 16 g/mol
3. (Original post by DoctorJem)
The number of moles of CO2 formed is the same as the number of moles of CuCO3, because when one molecule of CuCO3 decomposes it produces one molecule of CO2. So start by working out the number of moles of CuCO3 in 7.41g.
Atomic mass values:
Cu = 63.5 g/mol
C = 12 g/mol
O = 16 g/mol
I somehow got 2.64g, is this correct?
4. It certainly is. Well done!

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