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    Iodine is a grey-black solid that is not very soluble in water. Equilibrium 1 is set up with the equilibrium position well to the left.
    I 2(s) <-> I2 (aq)

    Solid iodine is much more soluble in an aqueous solution of potassium iodide, KI(aq), than in water.

    Equilibrium 2 is set up:

    I2 (aq) + I- (aq) <-> I3- (aq).


    'Suggest why I2 is not very soluble in water'?
    It's only a 1 mark ans but I can't think what this might be- and yes I am aware this will be an easy answer
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    (Original post by Rxmxi)
    Iodine is a grey-black solid that is not very soluble in water. Equilibrium 1 is set up with the equilibrium position well to the left.
    I 2(s) <-> I2 (aq)

    Solid iodine is much more soluble in an aqueous solution of potassium iodide, KI(aq), than in water.

    Equilibrium 2 is set up:

    I2 (aq) + I- (aq) <-> I3- (aq).


    'Suggest why I2 is not very soluble in water'?
    It's only a 1 mark ans but I can't think what this might be- and yes I am aware this will be an easy answer
    Is the answer not something to do with the fact that I2 is a non polar molecule so it cannot form hydrogen bonds/interact with polar water molecules.
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    You need to explain why some substances dissolve in water and why some don't.
 
 
 
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