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    How do I get the answer t^-2/3 from the equation:
    (3root(t) * root(t^3) ) / t^(5/2)
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    (Original post by boyPogi20)
    How do I get the answer t^-2/3 from the equation:
    (3root(t) * root(t^3) ) / t^(5/2)
    u done it yet?
    get everything in terms of t to the power of something like 3root(t)=t^1/3
    split into two fractions
    simplify
    then it gets difficult but that should be the way
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    I have tried it but I really don't get it. So far I got (t^1/3 * t^3/1) / t^5/2
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    The answer I got in the end is t^10/6 which is not the answer I'm looking for
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    (Original post by boyPogi20)
    I have tried it but I really don't get it. So far I got (t^1/3 * t^3/1) / t^5/2
    are you sure you wrote the second term correct ?
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    I'm not entirely sure. I would think that sqrt(t^3) would come out as a t^3/1.
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    (Original post by boyPogi20)
    I'm not entirely sure. I would think that sqrt(t^3) would come out as a t^3/1.
    you do know that sqrt(t^1)=t^1/2 and sqrt(t^2)= t^2/2=t then sqrt(t^3)= ?
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    3/2?
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    (Original post by boyPogi20)
    3/2?
    yep , now try to calculate the expression and your answer should be t^( -2/3)
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    So I got (t^-13/6) + (t^-2/2) and I get t^19/6. when I add the denominator t^5/2 I get the answer I'm looking for but I'm not sure if this is the correct method.
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    just so you know, it is an expression, not an equation.
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    (Original post by boyPogi20)
    So I got (t^-13/6) + (t^-2/2) and I get t^19/6. when I add the denominator t^5/2 I get the answer I'm looking for but I'm not sure if this is the correct method.
    ok , so let me break it down to you

    you have t^1/3 * t^3/2 and I think you know that t^a * t^b = t^(a+b)
    this result is divided by t^5/2 and you know that t^a / t^b = t^(a-b)
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    yep that makes sense but I can't seem to get t^-2/3
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    (Original post by boyPogi20)
    yep that makes sense but I can't seem to get t^-2/3
    how ? did you get to an expression t^(something + something - something) ?
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    That was the answer the teacher gave I'm just trying to find out how he did that
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    (Original post by boyPogi20)
    That was the answer the teacher gave I'm just trying to find out how he did that
    so you said you know t^a * t^b=t^(a+b)
    and t^a/t^b = t^(a-b) try then what (t^a+t^b)/t^c = ? try to use both formulas
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    I have tried that but still not the answer I'm looking for
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    (Original post by boyPogi20)
    I have tried that but still not the answer I'm looking for
    why? what does t^(a+b)/t^c = ?
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    I got the answer now, thanks for all the help
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    (3root(t) * root(t^3) ) / t^(5/2)
    3root(t) = t1/3
    root(t^3) = (t3)1/2 = t3/2

    ( t1/3 x t3/2 ) / t5/2
    When you multiply indices with the same base (t) you add the powers
    = t(1/3 + 3/2) / t5/2
    Change denominator of fractions so you can add them
    =t(2/6 + 9/6) / t5/2
    = t 11/6 / t5/2
    When you divide indices with the same base (t) you subtract the powers
    = t (11/6 - 5/2)
    Change denominator of fractions so you can subtract them
    = t(11/6 - 15/6)
    = t -4/6
    Simplify fractional power
    = t-2/3

    Hope this is helpful
 
 
 
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