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# Algebra help watch

1. How do I get the answer t^-2/3 from the equation:
(3root(t) * root(t^3) ) / t^(5/2)
2. (Original post by boyPogi20)
How do I get the answer t^-2/3 from the equation:
(3root(t) * root(t^3) ) / t^(5/2)
u done it yet?
get everything in terms of t to the power of something like 3root(t)=t^1/3
split into two fractions
simplify
then it gets difficult but that should be the way
3. I have tried it but I really don't get it. So far I got (t^1/3 * t^3/1) / t^5/2
4. The answer I got in the end is t^10/6 which is not the answer I'm looking for
5. (Original post by boyPogi20)
I have tried it but I really don't get it. So far I got (t^1/3 * t^3/1) / t^5/2
are you sure you wrote the second term correct ?
6. I'm not entirely sure. I would think that sqrt(t^3) would come out as a t^3/1.
7. (Original post by boyPogi20)
I'm not entirely sure. I would think that sqrt(t^3) would come out as a t^3/1.
you do know that sqrt(t^1)=t^1/2 and sqrt(t^2)= t^2/2=t then sqrt(t^3)= ?
8. 3/2?
9. (Original post by boyPogi20)
3/2?
yep , now try to calculate the expression and your answer should be t^( -2/3)
10. So I got (t^-13/6) + (t^-2/2) and I get t^19/6. when I add the denominator t^5/2 I get the answer I'm looking for but I'm not sure if this is the correct method.
11. just so you know, it is an expression, not an equation.
12. (Original post by boyPogi20)
So I got (t^-13/6) + (t^-2/2) and I get t^19/6. when I add the denominator t^5/2 I get the answer I'm looking for but I'm not sure if this is the correct method.
ok , so let me break it down to you

you have t^1/3 * t^3/2 and I think you know that t^a * t^b = t^(a+b)
this result is divided by t^5/2 and you know that t^a / t^b = t^(a-b)
13. yep that makes sense but I can't seem to get t^-2/3
14. (Original post by boyPogi20)
yep that makes sense but I can't seem to get t^-2/3
how ? did you get to an expression t^(something + something - something) ?
15. That was the answer the teacher gave I'm just trying to find out how he did that
16. (Original post by boyPogi20)
That was the answer the teacher gave I'm just trying to find out how he did that
so you said you know t^a * t^b=t^(a+b)
and t^a/t^b = t^(a-b) try then what (t^a+t^b)/t^c = ? try to use both formulas
17. I have tried that but still not the answer I'm looking for
18. (Original post by boyPogi20)
I have tried that but still not the answer I'm looking for
why? what does t^(a+b)/t^c = ?
19. I got the answer now, thanks for all the help
20. (3root(t) * root(t^3) ) / t^(5/2)
3root(t) = t1/3
root(t^3) = (t3)1/2 = t3/2

( t1/3 x t3/2 ) / t5/2
When you multiply indices with the same base (t) you add the powers
= t(1/3 + 3/2) / t5/2
Change denominator of fractions so you can add them
=t(2/6 + 9/6) / t5/2
= t 11/6 / t5/2
When you divide indices with the same base (t) you subtract the powers
= t (11/6 - 5/2)
Change denominator of fractions so you can subtract them
= t(11/6 - 15/6)
= t -4/6
Simplify fractional power
= t-2/3

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Updated: October 14, 2017
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