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    Can you check what I’ve done posted below please. After that I also need to know the maximum value of 1/(2x^2+4x+9)
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    (Original post by Reece.W.J)
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    Two things:

    1. You can check it for yourself by expanding it again. Useful skill for the exam.

    2. For your follow up question, you posted something very similar here -

    https://www.thestudentroom.co.uk/sho...2#post74126882

    So what in particular are you finding difficult? Just the first part being correct?
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    (Original post by Kevin De Bruyne)
    Two things:

    1. You can check it for yourself by expanding it again. Useful skill for the exam.

    2. For your follow up question, you posted something very similar here -

    https://www.thestudentroom.co.uk/sho...2#post74126882

    So what in particular are you finding difficult? Just the first part being correct?
    So is the maximum value 1/(-6/4)
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    I've attempted the question myself but I managed to get a different answer:

    1) 2[x^2 + 2x + 5/2] = 0
    2) 2[(x^2 + 1)^2 - 1^2 + 5/2] = 0
    3) 2[(x + 1)^2 + 3/2] = 0
    4) (x + 1)^2 + 3 = 0

    Therefore my turning points would be:
    x = - 1
    y = 3
    or ( -1, 3 )

    To calculate your turning points, your X value is the value inside the bracket and your Y value is the value outside.
    I've also checked these using a calculator (casio fx-991EX) and got the same values I had worked out.
 
 
 
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