Hi
See in a summary questions (pg 55 AQA Chemistry (yr2) Oxford Ted Lister)
Calculate emf of 2H(+) + Pb ----> Pb (2+) + H2
E value Lead given as -0.13v and Hydrogen E value given as 0.00v (From a Table)
emf = E (red) - E (ox)
Pb 0-->2+ therefore loss 2 electrons (oxidized).
H +1 -->0 therefore gain 1 electon (reduced) E value given as 0.00v
emf = 0.00 - (-0.13)
emf =+ 0.13 v
However the answer in the back of the book gives 0.26v
Completed the other three questions similar to this one and got the right answer.
Is it me or the text book?
Many Thanks
OJ