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    Hi,
    I am presented with a question that reads 'Describe the geometrical transformation which maps the graph of x^2 - 7x + 2 onto y= (x-4)^2'.

    So far I know that the parabola of y = (x-4)^2 has moved 4 to the right.

    Do I need to quadratically solve the other equation and then compare the two? Or is there another method?

    Thanks!
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    (Original post by TeacupAndTragedy)
    Hi,
    I am presented with a question that reads 'Describe the geometrical transformation which maps the graph of x^2 - 7x + 2 onto y= (x-4)^2'.

    So far I know that the parabola of y = (x-4)^2 has moved 4 to the right.

    Do I need to quadratically solve the other equation and then compare the two? Or is there another method?

    Thanks!
    Try completing the square for x^2 - 7x + 2.
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    (Original post by TeacupAndTragedy)
    Hi,
    I am presented with a question that reads 'Describe the geometrical transformation which maps the graph of x^2 - 7x + 2 onto y= (x-4)^2'.

    So far I know that the parabola of y = (x-4)^2 has moved 4 to the right.

    Do I need to quadratically solve the other equation and then compare the two? Or is there another method?

    Thanks!
    sure why not? i mean factorise if that's what you mean and compare
    you can always reverse and expand the expression on the right and compare
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    (Original post by Notnek)
    Try completing the square for x^2 - 7x + 2.
    So I have (x-3.5)^2 -10.25.

    Would this mean that it is 3.5 to the right and 10.25 down?
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    (Original post by TeacupAndTragedy)
    So I have (x-3.5)^2 -10.25.

    Would this mean that it is 3.5 to the right and 10.25 down?
    No not quite. So you need to get from

    (x-3.5)^2 -10.25

    to

    (x-4)^2

    Think again about the transformations.
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    (Original post by Notnek)
    No not quite. So you need to get from

    (x-3.5)^2 -10.25

    to

    (x-4)^2

    Think again about the transformations.
    (x-3.5)^2 to (x-4)^2 has a 0.5 difference, so 0.5 to the right.

    ..And then 10.25 downwards?

    Sorry if I'm wrong
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    (Original post by TeacupAndTragedy)
    (x-3.5)^2 to (x-4)^2 has a 0.5 difference, so 0.5 to the right.

    ..And then 10.25 downwards?

    Sorry if I'm wrong
    Close but it's not downwards.

    You're going from (x-3.5)^2-10.25 to (x-4)^2 + 0.

    So think about the change from -10.25 to 0.
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    (Original post by Notnek)
    Close but it's not downwards.

    You're going from (x-3.5)^2-10.25 to (x-4)^2 + 0.

    So think about the change from -10.25 to 0.
    Upwards?

    (Thank you for your patience by the way!)
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    (Original post by TeacupAndTragedy)
    Upwards?

    (Thank you for your patience by the way!)
    Yes that's right.

    You don't need to worry about not getting something straight away here. Guiding students to the answer is the whole point of this forum
 
 
 
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