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Maths. Vectors.

Points P and Q have coordinates (1, -8) and (10, -2). N is a point on PQ such that PN:NQ=1:2.

a) Find the coordinates of N.

b) Calculate the magnitudes of OP, ON, and PN. Hence show that ONP is a right angle angle.


/honest to God struggling./
Original post by Amb.Smith.
Points P and Q have coordinates (1, -8) and (10, -2). N is a point on PQ such that PN:NQ=1:2.

a) Find the coordinates of N.

b) Calculate the magnitudes of OP, ON, and PN. Hence show that ONP is a right angle angle.


/honest to God struggling./


hey amber it's owen and same
Reply 2
Original post by mariejuana
hey amber it's owen and same


Original post by Amb.Smith.
Points P and Q have coordinates (1, -8) and (10, -2). N is a point on PQ such that PN:NQ=1:2.

a) Find the coordinates of N.

b) Calculate the magnitudes of OP, ON, and PN. Hence show that ONP is a right angle angle.


/honest to God struggling./


I wish i could give a worked solution but its against the rule.

But use the fact that there's a ratio within P and Q.

The way i would approach the first bit is to work out the x difference from Q to P (Qx - Px) then times it by the ratio scale, which would be 1/3,

Then you would know how many more x values the x value of N has to be from P and you can add that value to the x value of p.

Repeat the same thing with y coordinate.

P.S: PM me and i can help you more with actual numbers as i'm not a llowed to here.

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