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# help with rates of reaction? watch

1. hey guys
i was making notes of rates of reaction from my textbook and everything was good until i saw this in the textbook:

hope you can see the picture, but from experiments 2 to 3 in the textbook it says that the rate doubles. Either I'm missing something really obvious or I'm terrible at maths, but how does 6.40 x 10-8 double to 1.28 x 10-7?
Any help would be appreciated as I'm finding rates hard enough already
2. It's not comparing experiments 2 and 3. it is comparing experiments 1 and 2 and as you can see in the table the rate doubles from 1 to 2.
3. That’s comparing experiment one too experiment two, 2(3.20 x10-8)=6.4 x10-8.
4. Thanks for the help guys but no, the text book say (I'll even quote it):
"Comparing experiments 2 and 3:
O3 doubles and NO2 stays the same
the rate also doubles
the reaction is 1st order with respect to O3"

5. Think you've posted the wrong picture then or are just trolling
6. No, experiments one and two are to the power of -8, experiment three is too the power of -7, the figure for experiment two doubled is that of experiment three.
7. It might make more sense if you convert them into decimals rather than standard form, 6.4x10-8 multiplied by two is 1.28x10-7.
8. not trolling, @LawBr you're right thank you!!!
9. Think 2 and 3 double as well? crap at scientific notation though

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Updated: October 16, 2017
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