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What is the "angle of the direction of motion" in vectors? watch

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Size:  194.1 KBJust for b) I'm guessing it's the angle where the motion begins? Sounds like a silly question I know, but I just need to make sure. And I know how to work out the actual angle btw. Thank you.
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    (Original post by alextheowl)
    Name:  directiony.png
Views: 21
Size:  194.1 KBJust for b) I'm guessing it's the angle where the motion begins? Sounds like a silly question I know, but I just need to make sure. And I know how to work out the actual angle btw. Thank you.
    Not really sure what you're saying. It wants the angle that the velocity vector makes with the vector i (which is the horizontal vector)
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    I don't understand exactly what u mean.

    The direction of motion is given by a velocity vector.

    Imagine the velocity vector 1i+2j m/s. This means that eveey second the particle travels one metre east then 2 metres north.

    The direction of motion with respect to the horizontal unit vector i is always constant given the velocity is constant.

    So the angle between the velocity vector and i is the direction the particle is travelling in.

    Hope that made some sense. If not let me know and ill try a different way.
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    you get the angle by working with the horizontal & vertical components of the velocity vector. thus for the vector v = 3i + 4j the direction angle will be arctan ( 4/3 )
 
 
 

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