When asked to draw the graph of 1+ 2cos2x
For some reason it had intercepts at (pi/3) , which didn’t make sense to me because a horizontal stretch of half would lead to (pi/2)
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- Thread Starter
- 17-10-2017 19:50
- 17-10-2017 19:56
Solve the equation 1+2cos2x = 0 to find the intercepts if you're in doubt. It can be hard to find the roots just from thinking of transformations.