write the redox equation for the reaction of copper (ii) ion cu2+ and the iodide ion i-
i do not answer how the answer is: 2cu2+ +4i- --> 2CuI +I2
i got cu2+ +2i- ---> i2 + cu
how do you get this answer?
redox equation cu2+ and i- Watch
- Thread Starter
- 18-10-2017 12:17
- 18-10-2017 12:38
I- isn't a good enough reducing agent to reduce the Cu2+ all the way to Cu (o.n. +2 -> 0)
It can reduce the Cu2+ to Cu+, though (o.n. +1 -> +1)
You need 2I- in order to make an I2, hence why 2Cu2+ is needed (each Cu2+ can steal 1e- off each I-)
But since Cu+ ions don't exist in solution, CuI must ppt out, hence the need for the 3rd and 4th I- (which aren't oxidised).