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Differentiation question watch

1. How do you differentiate 4ln(x^2+1) ?
Thanks
2. Remember that .
3. This an example of the chain rule.
y = 4ln(x2+1)
Let u = x2 +1
u' = 2x
y = 4ln(u)
y' = 4/u

2x(4/(x2+1)) =8x/x2 +1

Hence the differential is: 8x/x2 + 1
4. (Original post by SamLopezF)
This an example of the chain rule.
Please don't post full solutions - it's against the rules of the forum
5. (Original post by SamLopezF)
This an example of the chain rule.
y = 4ln(x2+1)
Let u = x2 +1
u' = 2x
y = 4ln(u)
y' = 4/u

2x(4/(x2+1)) =8x/x2 +1

Hence the differential is: 8x/x2 + 1
Ahh thank you it makes sense now!

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