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    how would you simplify this?
    would the 4t become 4t^-1 or does the 3t^2 become 3t^-1?
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    (Original post by ihatePE)
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    how would you simplify this?
    would the 4t become 4t^-1 or does the 3t^2 become 3t^-1?
    let's carry on with what you have, so we can cancel 1 t from the top and the bottom right?

    then i guess that's the simplest form for now, it depends how you want to write it
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    (Original post by will'o'wisp2)
    let's carry on with what you have, so we can cancel 1 t from the top and the bottom right?

    then i guess that's the simplest form for now, it depends how you want to write it
    so [4(1+5t^2)] / 3t^-1? and then laws of indices apply etc?
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    (Original post by ihatePE)
    so [4(1+5t^2)] / 3t^-1? and then laws of indices apply etc?
    No - where are you getting 3t^-1 from?
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    (Original post by ihatePE)
    so [4(1+5t^2)] / 3t^-1? and then laws of indices apply etc?
    if you want to make a minus power remember that \dfrac{1}{3x} = \dfrac{1}{3} x^{-1}
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    (Original post by DFranklin)
    No - where are you getting 3t^-1 from?
    cos 4t/3t^2 = 4/3t^-1?
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    (Original post by ihatePE)
    cos 4t/3t^2 = 4/3t^-1?
    No, it isn't.

    \dfrac{4t}{3t^2} \neq \dfrac{4}{3t^{-1}}.

    It is however true that

    \dfrac{4t}{3t^2} = \dfrac{4}{3} t^{-1}.

    If you think what you wrote is equivalent to the 2nd expression, refer to the Asking Questions Guidelines and in particular the section on ambiguous expressions.
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    (Original post by DFranklin)
    No, it isn't.

    \dfrac{4t}{3t^2} \neq \dfrac{4}{3t^{-1}}.

    It is however true that

    \dfrac{4t}{3t^2} = \dfrac{4}{3} t^{-1}.

    If you think what you wrote is equivalent to the 2nd expression, refer to the Asking Questions Guidelines and in particular the section on ambiguous expressions.
    o i see how its supposed to be that now
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    expand it.
    times it by 3t^2
    minus 3t^2
    then simplify

    - what I would do... but probably wrong.
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    (Original post by DFranklin)
    No, it isn't.

    \dfrac{4t}{3t^2} \neq \dfrac{4}{3t^{-1}}.

    It is however true that

    \dfrac{4t}{3t^2} = \dfrac{4}{3} t^{-1}.

    If you think what you wrote is equivalent to the 2nd expression, refer to the Asking Questions Guidelines and in particular the section on ambiguous expressions.
    to clarify the simplest expression is [4(1+5t^2)] / 3t ?
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    (Original post by ihatePE)
    to clarify the simplest expression is [4(1+5t^2)] / 3t ?
    Yes.
 
 
 
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