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# Maths homework help watch

1. determine the coordinates of the points of intersection of the line y=x+11 and the curve y = x^2 + 10x +19
2. (Original post by ikrshafiq)
determine the coordinates of the points of intersection of the line y=x+11 and the curve y = x^2 + 10x +19
Both equations are y equals something. So set the two right-hand-sides of the equation equal to each other. You can simplify this to a quadratic and get x coordinates (there may be two). Then just substitute them into one of the original equations (use the simplest one ).
3. Put them into a linear equation and then solve:

x+11=x^2+10x+19
0=x^2+9x+8
Put into double brackets: (x+1)(x+8)=0
Solve to find the co-ordinates
4. (Original post by TheMindGarage)
Both equations are y equals something. So set the two right-hand-sides of the equation equal to each other. You can simplify this to a quadratic and get x coordinates (there may be two). Then just substitute them into one of the original equations (use the simplest one ).
is this correct:
x+11=x^2 +10x+19
x^2-9x+8
(x-1)(x-8)=0
x=1 or x=8
and then subtiute it in y=x + 11 to get the y values
5. eyyyyy
6. (Original post by ikrshafiq)
is this correct:
x+11=x^2 +10x+19
x^2-9x+8
(x-1)(x-8)=0
x=1 or x=8
and then subtiute it in y=x + 11 to get the y values
Should be +9x in the quadratic rather than -9x. You can double-check whatever answers you get by substituting into the other equation (y = x^2 + 10x +19) and checking whether you get the same.
7. (Original post by ikrshafiq)
is this correct:
x+11=x^2 +10x+19
x^2-9x+8
(x-1)(x-8)=0
x=1 or x=8
and then subtiute it in y=x + 11 to get the y values
I think it should be:

x+11=x^2+10x+19
0=x^2+9x+8 (because of x^2+10x+19-x-11)
0=(x+1)(x+8)
So x=-1 and x=-8

Then sub in to find y for each x value and you've got your coordinates
8. (Original post by Nikey)
I think it should be:

x+11=x^2+10x+19
0=x^2+9x+8 (because of x^2+10x+19-x-11)
0=(x+1)(x+8)
So x=-1 and x=-8

Then sub in to find y for each x value and you've got your coordinates
which one do u have to sub in y=x+11 or y=x^2+10x+19
9. (Original post by yemenia16)
which one do u have to sub in y=x+11 or y=x^2+10x+19
any
10. (Original post by yemenia16)
which one do u have to sub in y=x+11 or y=x^2+10x+19
Any would work. I'd do y=x+11 because it's quicker and easier.

So when x = -1, y=(-1)+11
and when x = -8, y=(-8)+11

And there's your 2 sets of coordinates.
(2k -3)^2=2x+(k-1)=0
where k is a constant, has real roots
a. show that 2k^2 - 5k +12 equal < 0

how would you do this guys???

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