Solve the equation:

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

Original post by Musicanor

Solve the equation:

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

Can you please rewrite your question/working using brackets? It's very hard to read.

Also, please post questions in the maths forum in future and you'll get a faster response. I've moved this one for you

Original post by Musicanor

Solve the equation:

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

It is not asking you to solve the equation but to write it in surd form

Original post by aspen fernandes

It is not asking you to solve the equation but to write it in surd form

The question is asking to solve the equation and write the solution in surd form.

x root 2 root 4=2x

Root2 times root4 is 2root2 not 2

Original post by Queenie123

x

I had to remove your post since it was a full solution, which is against the maths forum rules. Please read the posting guidelines at the top of the forum

Oh I didn’t realise sorry

Original post by Notnek

I had to remove your post since it was a full solution, which is against the maths forum rules. Please read the posting guidelines at the top of the forum

Original post by Musicanor

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

Check your working here

Original post by Musicanor

10+x root 8= 6x divided by root 2

Give your answer in the form a root b where a and b are integers

Are my workings correct?

10+ x root 8= 6x divided by root 2

10+ x root 2 root 4= 6x divide root 2

10+2x=6x

10=4x

10/4=x

5/2=x

X= 2.5

When I substitute it in it doesn't equate

Many thanks for your help

this is as far as i got i don't know if it's right

10+x root 8 = 6x/root 2

10+x root 4 root 2= 6x/root2

10+2xroot2=6x/root2 * root2/root2

10+2xroot2=6xroot2/2

20+x root 2

maybe correct me if I am wrong pleased anyone

Original post by aspen fernandes

this is as far as i got i don't know if it's right

10+x root 8 = 6x/root 2

10+x root 4 root 2= 6x/root2

10+2xroot2=6x/root2 * root2/root2

10+2xroot2=6xroot2/2

20+x root 2

maybe correct me if I am wrong pleased anyone

10+x root 8 = 6x/root 2

10+x root 4 root 2= 6x/root2

10+2xroot2=6x/root2 * root2/root2

10+2xroot2=6xroot2/2

20+x root 2

maybe correct me if I am wrong pleased anyone

Okay thanks everyone

Original post by aspen fernandes

this is as far as i got i don't know if it's right

10+x root 8 = 6x/root 2

10+x root 4 root 2= 6x/root2

10+2xroot2=6x/root2 * root2/root2

10+2xroot2=6xroot2/2

20+x root 2

maybe correct me if I am wrong pleased anyone

10+x root 8 = 6x/root 2

10+x root 4 root 2= 6x/root2

10+2xroot2=6x/root2 * root2/root2

10+2xroot2=6xroot2/2

20+x root 2

maybe correct me if I am wrong pleased anyone

what did you do there?

What i got aswell

Original post by KarthikK123

What i got aswell

Original post by begbie68

Your mistake is on the 3rd line.

should be

10root2 + 4x = 6x

You need to multiply your 2nd line by root2 ..... every term is multiplied

should be

10root2 + 4x = 6x

You need to multiply your 2nd line by root2 ..... every term is multiplied

Old thread.

Original post by sumaiya_j

Such an old thread but the answers 5\root2 for anyone wondering. Hope everyone's doing well :')

Thank you , 3 years ago!

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