Turn on thread page Beta
 You are Here: Home >< Physics

# Thermodynamics - work done in a complete carnot cycle watch

1. I am trying to revise at the moment to prepare for an exam, and I am stuck on one question that I have seen. The question asks to work out the work done with the following values:
Th=673 K
TL=264K
V1=14.2m^3/Kg
P2=98.8 KPa
R = 0.287 KJ/Kg
Gamma= 1.4

Can I get any help on the equations that should be used for this? and the steps that are needed. Don't worry about calculations

Thanks for your help!
2. (Original post by zeesus69)
I am trying to revise at the moment to prepare for an exam, and I am stuck on one question that I have seen. The question asks to work out the work done with the following values:
Th=673 K
TL=264K
V1=14.2m^3/Kg
P2=98.8 KPa
R = 0.287 KJ/Kg
Gamma= 1.4

Can I get any help on the equations that should be used for this? and the steps that are needed. Don't worry about calculations

Thanks for your help!
Well, you can look up the standard result for the work done by a Carnot cycle. If there are any additional values that you need, I guess that it's possible to find them from the information provided, by using the equations relating the pressures and volumes in the adiabatic/isothermal sections of the cycle.

I assume that you have a diagram and know which parts of the cycle the V1 and P2 values apply to? It's not clear to me.

Turn on thread page Beta
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: October 21, 2017
Today on TSR

### University open days

• University of East Anglia (UEA)
Could you inspire the next generation? Find out more about becoming a Secondary teacher with UEA… Postgraduate
Thu, 18 Oct '18
• University of Warwick
Sat, 20 Oct '18
• University of Sheffield