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Thermodynamics - work done in a complete carnot cycle watch

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    I am trying to revise at the moment to prepare for an exam, and I am stuck on one question that I have seen. The question asks to work out the work done with the following values:
    Th=673 K
    TL=264K
    V1=14.2m^3/Kg
    P2=98.8 KPa
    R = 0.287 KJ/Kg
    Gamma= 1.4

    Can I get any help on the equations that should be used for this? and the steps that are needed. Don't worry about calculations

    Thanks for your help!
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    (Original post by zeesus69)
    I am trying to revise at the moment to prepare for an exam, and I am stuck on one question that I have seen. The question asks to work out the work done with the following values:
    Th=673 K
    TL=264K
    V1=14.2m^3/Kg
    P2=98.8 KPa
    R = 0.287 KJ/Kg
    Gamma= 1.4

    Can I get any help on the equations that should be used for this? and the steps that are needed. Don't worry about calculations

    Thanks for your help!
    Well, you can look up the standard result for the work done by a Carnot cycle. If there are any additional values that you need, I guess that it's possible to find them from the information provided, by using the equations relating the pressures and volumes in the adiabatic/isothermal sections of the cycle.

    I assume that you have a diagram and know which parts of the cycle the V1 and P2 values apply to? It's not clear to me.
 
 
 

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