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    Hi, I have been working on this problem for a while and am unable to find the mark scheme. Any help would be greatly appreciated!
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    (Original post by rugbycricket)
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    Hi, I have been working on this problem for a while and am unable to find the mark scheme. Any help would be greatly appreciated!
    radius bisects a chord in half is something u need - if that helps
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    Draw a line parallel with AE that starts at B and meets the other side of the circle at a new point F. By symmetry, and because AD = 4cm, the length of BF will be 40 + 2x4. Now you have a right angled triangle CBF with all three points touching the circumference of the circle. That will enable you to invoke a well known circle theorem. (Hint: what is CF, in terms of the circle?).
 
 
 
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