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    The volume of hydrogen required to make 71 Litres of HCL is?
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    71L = 71 dm^3

    So I presume 71 dm^3 of Hydrogen is needed?
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    (Original post by S.H.Rahman)
    71L = 71 dm^3

    So I presume 71 dm^3 of Hydrogen is needed?
    You'd be wrong.

    Try balancing the equation and you'll see why.

    ALSO, the Q is rather ambiguous, does the OP mean 71 dm3 of gaseous HCl, or a solution and if so of what conc?

    I could be pedantic and point out that the reaction is rather exothermic and would cause an increase in pressure, which would lead to an increase in volume. But I won't.
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    Question is extremely ambiguous as said by Pigster ... But, if we *assume* the question implies this formula:
    H2(g) + Cl2(g) -> 2HCl(g)

    Mole ratio 1:1:2

    Any mole of gas occupies 24 litres of volume. If there is 71 litres of HCl gas, that means there is approx 2.96mol of HCl. Using mol ratio, that means 1.48mol of H2.

    1.5 x 24 = 35.5

    35.5 litres

    (please correct me if wrong)
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    You are all wrong, the answer is obviously Fish
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    (Original post by Avaia)
    You are all wrong, the answer is obviously Fish
    How could I have been so foolish?

    [/kicks self]
 
 
 
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