The volume of hydrogen required to make 71 Litres of HCL is?
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- Thread Starter
- 21-10-2017 18:50
- 21-10-2017 18:55
71L = 71 dm^3
So I presume 71 dm^3 of Hydrogen is needed?
- 21-10-2017 19:03
Try balancing the equation and you'll see why.
ALSO, the Q is rather ambiguous, does the OP mean 71 dm3 of gaseous HCl, or a solution and if so of what conc?
I could be pedantic and point out that the reaction is rather exothermic and would cause an increase in pressure, which would lead to an increase in volume. But I won't.
- 21-10-2017 21:03
Question is extremely ambiguous as said by Pigster ... But, if we *assume* the question implies this formula:
H2(g) + Cl2(g) -> 2HCl(g)
Mole ratio 12
Any mole of gas occupies 24 litres of volume. If there is 71 litres of HCl gas, that means there is approx 2.96mol of HCl. Using mol ratio, that means 1.48mol of H2.
1.5 x 24 = 35.5
(please correct me if wrong)Last edited by kilner; 21-10-2017 at 23:09.
- 21-10-2017 21:06
You are all wrong, the answer is obviously Fish
- 22-10-2017 09:38