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Manipulating an image watch

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    Can you help me with this please.

    Image resolution: 10m per pixel, covers 100km^2
    how many pixels required to achieve the resolution.

    i tried: \frac{10,000}{10} which gave me 100 but the answer is 1x10^6
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    (Original post by joyoustele)
    100 100 100
    100 200 100
    100 100 100

    ai) i was asked to replace the middle pixel, with the median of all values.The Answer is 111. But i cant see how. Please help
    I think that they should have written "mean of all values".
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    (Original post by atsruser)
    I think that they should have written "mean of all values".
    i meant mean, sorry, nevermind i got it. I think i typed it in wrong before
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    (Original post by atsruser)
    I think that they should have written "mean of all values".
    Can you help me with this please.

    Image resolution: 10m per pixel, covers 100km^2
    how many pixels required to achieve the resolution.

    i tried: \frac{10,000}{10} which gave me 100 but the answer is 1x10^6
 
 
 
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