Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    • Thread Starter
    Offline

    14
    ReputationRep:
    Please can someone help me with this question?

    A calorimeter consists of 140g of aluminium and 300g of water. 6100J of heat raises its temperature by 4.42K. Calculate

    a) its heat capacity
    b) the specific heat capacity of aluminium
    Online

    17
    ReputationRep:
    For part a it is a matter of rearranging Q=mcT for c and subbing in values.

    For part b, multiply ur answer in a by the total mass in a. Then as u know the specific heat capacity of water u can multiply this by the mass of water. The difference between these is the specific heat capacity of aluminium multiplied by the mass of aluminium.
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    14
    ReputationRep:
    (Original post by Shaanv)
    For part a it is a matter of rearranging Q=mcT for c and subbing in values.

    For part b, multiply ur answer in a by the total mass in a. Then as u know the specific heat capacity of water u can multiply this by the mass of water. The difference between these is the specific heat capacity of aluminium multiplied by the mass of aluminium.
    Thank you for the reply but for part b) I am still getting the wrong answer?
    Online

    17
    ReputationRep:
    (Original post by BobbiBlue)
    Thank you for the reply but for part b) I am still getting the wrong answer?
    My bad my method was over complicated and wrong and I apologise.

    So as u know the specific heat capacity of water u can work out how much energy was used to heat the water.

    So the rest of the energy supplied was used to heat up the aluminium. As u now know the energy required the mass of aluminium and the temperature change u can work out its specific heat capacity.

    Hope this helped.
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    14
    ReputationRep:
    (Original post by Shaanv)
    My bad my method was over complicated and wrong and I apologise.

    So as u know the specific heat capacity of water u can work out how much energy was used to heat the water.

    So the rest of the energy supplied was used to heat up the aluminium. As u now know the energy required the mass of aluminium and the temperature change u can work out its specific heat capacity.

    Hope this helped.

    Do I still need to use part a) for part b)?
    Online

    17
    ReputationRep:
    (Original post by BobbiBlue)
    Do I still need to use part a) for part b)?
    Nope just the initial information in the question👊🏾
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    14
    ReputationRep:
    Thank you so much!!!
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: October 22, 2017
Poll
Do you like carrot cake?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.