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# Differentiation help watch

1. Can someone help with any of these please??!!!!
2. (Original post by Lucyperks7)

Can someone help with any of these please??!!!!
Have you tried anything?
3. 1: use implicit differentiation

2: find dx/dy & then get dy/dx

3: parametric differentiation: dy/dx = dy/dt divided by dx/dt
4. (Original post by RDKGames)
Have you tried anything?
Yes I’ve done most sorry, sounds stupid but I forgot how to do part 1(b) how to find the Y coordinate
5. (Original post by Lucyperks7)
Yes I’ve done most sorry, sounds stupid but I forgot how to do part 1(b) how to find the Y coordinate
Sub in and then solve for
6. Does y = 1/2, therefore gradient will = 23/16?
7. (Original post by the bear)
1: use implicit differentiation

2: find dx/dy & then get dy/dx

3: parametric differentiation: dy/dx = dy/dt divided by dx/dt
So for question 2, is the answer 1/3sec^2 3y
8. (Original post by Lucyperks7)
So for question 2, is the answer 1/3sec^2 3y
yes... dy/dx = 1/{3sec2 3y}

which can be written another way because sec y ≡ 1/cos y

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