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# Mechanics M2. Stuck (projectiles) watch

1. A golfer strikes a ball with speed 60ms-1. The ball lands in a bunker at the same level, 210 metres away. Calculate possible angles of projection.

My working:
......... ......
........ ......
............
..............

Substituting t into S=ut+0.5at^2

i then went on and moved the equation to the R.H.S and put my values in the quadratic formula. Did i make a mistake? is this how im supposed to do it?
2. Okay penultimate line, times by cos^2 (and change tan into sin/cos). You can then use one of the double angle identities in reverse so you can get 1 trig function which you can then solve. Your last line is completely wrong btw.
3. Never mind i solved it, Turns out when i moved everything to the R.H.S i got one of the signs wrong( put + instead of -)
Okay penultimate line, times by cos^2 (and change tan into sin/cos). You can then use one of the double angle identities in reverse so you can get 1 trig function which you can then solve. Your last line is completely wrong btw.
I managed to get the answer. Using my last line
5. (Original post by joyoustele)
I managed to get the answer. Using my last line
Ohhh I didn't spot you using sec^2=1+tan^2 . I still think my way is easier but of course it works as long as the identities you use are correct .
6. The working for this is a bit easier overall IMHO if you first obtain an expression for t from the vertical motion of the golf ball. (t = ([email protected])/g). If you substitute that “t” in the expression for horizontal motion, you end up with quite a benign trig formula in terms of [email protected]
7. A lovely trick here to find the solution easier is to factorise:

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